6+2[3j-2]=4[1+j]

Solution for 6+2[3j-2]=4[1+j] equation:

Simplifying
6 + 2[3j + -2] = 4[1 + j]

Reorder the terms:
6 + 2[-2 + 3j] = 4[1 + j]
6 + [-2 * 2 + 3j * 2] = 4[1 + j]
6 + [-4 + 6j] = 4[1 + j]

Combine like terms: 6 + -4 = 2
2 + 6j = 4[1 + j]
2 + 6j = [1 * 4 + j * 4]
2 + 6j = [4 + 4j]

Solving
2 + 6j = 4 + 4j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-4j' to each side of the equation.
2 + 6j + -4j = 4 + 4j + -4j

Combine like terms: 6j + -4j = 2j
2 + 2j = 4 + 4j + -4j

Combine like terms: 4j + -4j = 0
2 + 2j = 4 + 0
2 + 2j = 4

Add '-2' to each side of the equation.
2 + -2 + 2j = 4 + -2

Combine like terms: 2 + -2 = 0
0 + 2j = 4 + -2
2j = 4 + -2

Combine like terms: 4 + -2 = 2
2j = 2

Divide each side by '2'.
j = 1

Simplifying
j = 1